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Verse Dt3126b states
Take this book of the law, and put it by the side of the ark of the covenant of HaShem your Gd, that it may be there for a witness against thee.
Rashi explains this verse with a numerically labelled diagram
ARK 15 handbreadths = 2.5 Cubits
'                     
' 9  
'  
'  Two tablets(10 commandments) 
' 9  6 x 6 + 6 x 6 = 12 x 6 Sefer  9 HANDBREADTHS = 1.5 cubits
Torah
'  2 x 8 
'  
' 9  
'                     
Here is a rough overview of computations
 The ark was 1.5 x 2.5 cubits or 9 handbreadths by 15 handbreadths
 The 10 commandments were written on two tablets of stone
 Each tablet was 1 cubit x 1 cubit or 6 handbreadths by 6 handbreadths
 Hence two tablets were 12 handbreadths by 6 handbreadths
 The length of the ark had 15 handbreadths or 3 more than 12 handbreadths left over
 The boards were each half a handbreath in width so we have 32*1/2 = 2 handbreadths left over
 Similarly since the width of the boards were 1/2 handbreadth we have 92*1/2=8 handbreadths
 So after placing the two tablets in the ark we have space left for 2 x 8 handbreadths which is 8 x 32 inches
 We can argue that the Scroll of Torah Law occupied 8 x 32 inches and laid in the ark
 The diagram above illustrates this.
Advanced Rashi:There are many problems with the above approach.
 We still have room leftover on the
sides since the tablets were 6 handbreadths and there are 23
handbreadths left over (Some say the broken chips of the first
tablets are there).
 The above calculations follow the opinion that each cubit is 6 handbreadths.
There are opinions that each cubit was 5 not 6 handbreadths only
giving us 12.5 handbreadths length.
The major point to take
away is that Rashi interprets the verselet place the Torah
by the side of the ark to mean The Torah was placed in
the ark and there was room for it there. However there is much conjecture
in Rashi's diagram  albeit it is reasonable.

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