####################################################### # 12 YEAR Ayelet DAILY-RASHI-YOMI CYCLE # # AUG 31 th, 2006 # # Rashis 3665-3666 Of 7700 (47.6%) # # # # VISIT THE RASHI YOMI ARCHIVES # # ----------------------------- # # http://www.RashiYomi.Com/thismon.htm # # # # Reprinted with permission from Rashi-is-Simple, # # (c) 1999-2004, RashiYomi Inc., Dr Hendel President # # Permission to reprint with this header PROVIDED # # it is not printed for profit # # # # WARNING: READ with COURIER 10 (Fixed width) FONTS# # # ####################################################### |
#*#*# (C) RashiYomi Inc. 2005, Dr. Hendel, President #*#*#
VERSE: Dt23-12a
RASHIS COVERED: Dt21-17a Dt23-12a
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(C) Dr Hendel, Jan-04 | ||
SUCCINCT SUMMARY: ----------------- One of Rashis 10 major goals is to illustrate complex geometric designs or algebraic complications. This is called the Rashi method of SPREADSHEETS, since SPREADSHEETS are one method of clarifying a complex relationship. The SPREADSHEET method can refer to any illustration of a verse that clarifies it. EXAMPLE Dt21-17a ---------------- Dt21-17a states that the 1st-born ---------------------------------- the 1st born child inherits DOUBLE ---------------------------------- A numerical ALGORITHM for explaining double is presented by Rashi. First we present the algorithm for equal inheritance. If All inherit equally ---------------------- Father has 3 boys Father has $120 If All inherit equally Each boy inherits 120/3=$40 ---------------------- ---------------------------------------- If Eldest gets double ---------------------- ---------------------------------------- Create fictitious child Father has 4 boys: 3 Real+1 fictitious All inherit equally Each boy receives 120/4=$30 Eldest gets double Eldest gets his $30+$30 of fictitioius=$60 Remaining children Get 120/4 = 30*1 ---------------------- ---------------------------------------- It APPEARS that formula is - Eldest gets - 120/(3+1) x 2 - Others get - 120/(3+1) Eldest then has double of other children As shown in LIST690n below which summarizes this argument, this is not exactly true. An exotic example from the Rambam shows the necessity of using the method in the table. EXAMPLE Dt23-12 --------------- The text of Dt23-12 states ------------------------------------- And it will be that as evening comes he washes his body in water and when sunset comes he will be pure ------------------------------------- There are two LOGICALLY EQUIVALENT ways of reading this verse METHOD 1 ------------------------------------- IF (he washes before sunset AND waits till after sunset) THEN (He is PURE)*10 ------------------------------------- METHOD 2 ------------------------------------- IF (He washes before sunset THEN IF (He waits till sunset THEN (He is pure)))*10 ------------------------------------- The equivalence of these two methods is known as the EXPORT-IMPORT law of LOGIC. So Rashi simply clarifies requirements here. LIST690a below presents many Rashis based on SPREADSHEETS | ||
| ITEM | DETAIL | |
| RASHI RULE CLASS: | SPREADSHEETS | |
| RASHI SUBRULE CLASS | ALGEBRA | |
| RASHI WORKBOOK PRINCIPLE | #30 | |
| SEE BELOW | LIST690a | |
| List of Rashis using | Spreadsheets/Algebra | |
| ----------------------- | ---------------------------------------- | |
| SEE BELOW | LIST690n | |
| Illustration of | Eldest Inheriting Double | |
| ----------------------- | ---------------------------------------- | |
| SEE BELOW | LIST690O | |
| Illustration of | (A and B)==>C vs A==>(B==>C) | |
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(C) Dr Hendel, Jan-04 | ||
Illustration of Eldest Inheriting Double | ||
| CASE | CONSEQUENCE | |
| If all inherit equally | ||
| ----------------------- | ||
| Father has | 3 boys | |
| Father has | $120 | |
| If All inherit equally | Each boy inherits $120/3=$40 | |
| ---------------------- | ---------------------------------------- | |
| If Eldest gets double | ||
| ---------------------- | ---------------------------------------- | |
| Create fictitious child | Father has 4 boys: 3 Real+1 fictitious | |
| All inherit equally | Each boy receives $120/4=$30 | |
| Eldest gets double | Eldest gets his $30+$30 of fictitioius=$60 | |
| Remaining children | Get 120/4 = 30*1 | |
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*1 So it APPEARS that formula is - Eldest gets - 120/(3+1) x 2 - Others get - 120/(3+1) Eldest then has double of other children But Rambam gives an unusual case - 1 ordinary boy - 1 eldest - 1 Hidden-sex child The Hidden-sex child - has a right to inherit - does not have a right to intefer with eldest share This creates some complicated arithmetic which follows the outline above (Rambam: Inheritance Chapter 2) | ||